200 lines
5.2 KiB
Python
200 lines
5.2 KiB
Python
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import numpy as np
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from warnings import warn
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from ._basic import rfft, irfft
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from ..special import loggamma, poch
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from scipy._lib._array_api import array_namespace, copy
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__all__ = ['fht', 'ifht', 'fhtoffset']
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# constants
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LN_2 = np.log(2)
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def fht(a, dln, mu, offset=0.0, bias=0.0):
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xp = array_namespace(a)
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a = xp.asarray(a)
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# size of transform
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n = a.shape[-1]
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# bias input array
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if bias != 0:
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# a_q(r) = a(r) (r/r_c)^{-q}
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j_c = (n-1)/2
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j = xp.arange(n, dtype=xp.float64)
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a = a * xp.exp(-bias*(j - j_c)*dln)
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# compute FHT coefficients
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u = xp.asarray(fhtcoeff(n, dln, mu, offset=offset, bias=bias))
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# transform
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A = _fhtq(a, u, xp=xp)
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# bias output array
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if bias != 0:
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# A(k) = A_q(k) (k/k_c)^{-q} (k_c r_c)^{-q}
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A *= xp.exp(-bias*((j - j_c)*dln + offset))
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return A
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def ifht(A, dln, mu, offset=0.0, bias=0.0):
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xp = array_namespace(A)
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A = xp.asarray(A)
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# size of transform
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n = A.shape[-1]
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# bias input array
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if bias != 0:
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# A_q(k) = A(k) (k/k_c)^{q} (k_c r_c)^{q}
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j_c = (n-1)/2
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j = xp.arange(n, dtype=xp.float64)
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A = A * xp.exp(bias*((j - j_c)*dln + offset))
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# compute FHT coefficients
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u = xp.asarray(fhtcoeff(n, dln, mu, offset=offset, bias=bias, inverse=True))
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# transform
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a = _fhtq(A, u, inverse=True, xp=xp)
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# bias output array
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if bias != 0:
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# a(r) = a_q(r) (r/r_c)^{q}
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a /= xp.exp(-bias*(j - j_c)*dln)
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return a
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def fhtcoeff(n, dln, mu, offset=0.0, bias=0.0, inverse=False):
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"""Compute the coefficient array for a fast Hankel transform."""
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lnkr, q = offset, bias
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# Hankel transform coefficients
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# u_m = (kr)^{-i 2m pi/(n dlnr)} U_mu(q + i 2m pi/(n dlnr))
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# with U_mu(x) = 2^x Gamma((mu+1+x)/2)/Gamma((mu+1-x)/2)
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xp = (mu+1+q)/2
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xm = (mu+1-q)/2
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y = np.linspace(0, np.pi*(n//2)/(n*dln), n//2+1)
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u = np.empty(n//2+1, dtype=complex)
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v = np.empty(n//2+1, dtype=complex)
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u.imag[:] = y
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u.real[:] = xm
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loggamma(u, out=v)
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u.real[:] = xp
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loggamma(u, out=u)
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y *= 2*(LN_2 - lnkr)
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u.real -= v.real
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u.real += LN_2*q
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u.imag += v.imag
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u.imag += y
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np.exp(u, out=u)
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# fix last coefficient to be real
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u.imag[-1] = 0
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# deal with special cases
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if not np.isfinite(u[0]):
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# write u_0 = 2^q Gamma(xp)/Gamma(xm) = 2^q poch(xm, xp-xm)
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# poch() handles special cases for negative integers correctly
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u[0] = 2**q * poch(xm, xp-xm)
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# the coefficient may be inf or 0, meaning the transform or the
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# inverse transform, respectively, is singular
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# check for singular transform or singular inverse transform
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if np.isinf(u[0]) and not inverse:
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warn('singular transform; consider changing the bias', stacklevel=3)
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# fix coefficient to obtain (potentially correct) transform anyway
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u = copy(u)
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u[0] = 0
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elif u[0] == 0 and inverse:
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warn('singular inverse transform; consider changing the bias', stacklevel=3)
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# fix coefficient to obtain (potentially correct) inverse anyway
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u = copy(u)
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u[0] = np.inf
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return u
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def fhtoffset(dln, mu, initial=0.0, bias=0.0):
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"""Return optimal offset for a fast Hankel transform.
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Returns an offset close to `initial` that fulfils the low-ringing
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condition of [1]_ for the fast Hankel transform `fht` with logarithmic
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spacing `dln`, order `mu` and bias `bias`.
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Parameters
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----------
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dln : float
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Uniform logarithmic spacing of the transform.
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mu : float
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Order of the Hankel transform, any positive or negative real number.
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initial : float, optional
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Initial value for the offset. Returns the closest value that fulfils
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the low-ringing condition.
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bias : float, optional
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Exponent of power law bias, any positive or negative real number.
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Returns
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-------
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offset : float
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Optimal offset of the uniform logarithmic spacing of the transform that
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fulfils a low-ringing condition.
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Examples
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--------
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>>> from scipy.fft import fhtoffset
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>>> dln = 0.1
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>>> mu = 2.0
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>>> initial = 0.5
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>>> bias = 0.0
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>>> offset = fhtoffset(dln, mu, initial, bias)
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>>> offset
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0.5454581477676637
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See Also
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--------
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fht : Definition of the fast Hankel transform.
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References
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----------
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.. [1] Hamilton A. J. S., 2000, MNRAS, 312, 257 (astro-ph/9905191)
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"""
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lnkr, q = initial, bias
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xp = (mu+1+q)/2
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xm = (mu+1-q)/2
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y = np.pi/(2*dln)
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zp = loggamma(xp + 1j*y)
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zm = loggamma(xm + 1j*y)
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arg = (LN_2 - lnkr)/dln + (zp.imag + zm.imag)/np.pi
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return lnkr + (arg - np.round(arg))*dln
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def _fhtq(a, u, inverse=False, *, xp=None):
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"""Compute the biased fast Hankel transform.
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This is the basic FFTLog routine.
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"""
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if xp is None:
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xp = np
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# size of transform
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n = a.shape[-1]
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# biased fast Hankel transform via real FFT
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A = rfft(a, axis=-1)
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if not inverse:
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# forward transform
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A *= u
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else:
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# backward transform
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A /= xp.conj(u)
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A = irfft(A, n, axis=-1)
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A = xp.flip(A, axis=-1)
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return A
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